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$${\displaystyle \int \left( 2 x- 6\right)\ e^{-x}\ dx}$$
\({ \frac{10}{3}\ e^{9x} + C}\)
\({\left(- 2 x+ 4\right)\ e^{-x} + C}\)
\({\left(- \frac{15}{2} x- \frac{17}{4}\right)\ e^{-6x} + C}\)
\({\left(- 3 x^{2}- 4 x- \frac{10}{3}\right)\ e^{6x} + C}\)